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Is there a scanner that can work out cubic centimetres?
K2-K6:
--- Quote from: Charlie J on December 14, 2021, 12:03:38 AM ---I’m not sure that would work, as displacement is related to volume and not surface area. You could work out cubic centimetres by this method but not square centimetres. Two objects can have the same volume but different surface areas.
--- End quote ---
I'm kind of thinking out loud which with our collective thoughts may shed some light on a concise direction.
"Two objects can have the same volume but different surface areas." Would that not demonstrate different densities? Of material.
Trying to think of an example that would have different volume (irrespective of material density) and still be the same surface area. Isn't volume the space included within the specified surface area ? And so would change in a fixed relationship.
K2-K6:
Or, "The density of steel is in the range of 7.75 and 8.05 g/cm3 (7750 and 8050 kg/m3 or 0.280 and 0.291 lb/in3). The theoretical density of mild steel (low-carbon steel) is about 7.87 g/cm3 (0.284 lb/in3).
Density of carbon steels, alloy steels, tool steels and stainless steels are shown below in g/cm3, kg/m3 and lb/in3."
From this site https://amesweb.info/Materials/Density_of_Steel.aspx which would mean, if you weigh the components, each 7.87 gram would occupy a cubic centimeter, which gives the maths route to calculate total surface area for plating.
Which looks to me that you can reliably give a surface area for the components as mass of the low carbon steel is a constant.
Is that true ?
Charlie J:
--- Quote from: K2-K6 on December 14, 2021, 08:16:11 AM ---Or, "The density of steel is in the range of 7.75 and 8.05 g/cm3 (7750 and 8050 kg/m3 or 0.280 and 0.291 lb/in3). The theoretical density of mild steel (low-carbon steel) is about 7.87 g/cm3 (0.284 lb/in3).
Density of carbon steels, alloy steels, tool steels and stainless steels are shown below in g/cm3, kg/m3 and lb/in3."
From this site https://amesweb.info/Materials/Density_of_Steel.aspx which would mean, if you weigh the components, each 7.87 gram would occupy a cubic centimeter, which gives the maths route to calculate total surface area for plating.
Which looks to me that you can reliably give a surface area for the components as mass of the low carbon steel is a constant.
Is that true ?
--- End quote ---
Unfortunately it's not that simple. Volume = mass/density. So two objects with the same mass and density will have the same volume. However, two objects with the same mass and density can have two completely different surface areas. For example, a cube of mild steel measuring 1cm x 1cm x1cm would indeed have a mass of 7.87 gm/cm3. However, if you hammered the cube into a plate say 2mm thick, it would have the same mass, the same density and therefore the same volume but a much larger surface area.
Probably the simplest and cheapest means of determining the surface area of a complex shape is to cover the surface area with tin foil and then flatten out and measure the tinfoil.
K2-K6:
Trying to get my mind around it :)
"For example, a cube of mild steel measuring 1cm x 1cm x1cm would indeed have a mass of 7.87 gm/cm3. However, if you hammered the cube into a plate say 2cm thick, it would have the same mass, the same density and therefore the same volume but a much larger surface area."
I don't think that holds true. If you hammered a 1cm cube it could never be 2cm thick. As you hammered it the top and bottom surface area increase but with the height reduced with every blow. It's still the same maths although not an even 1cm uniformity.
Charlie J:
Modified the post to say 2mm to correct the 2cm typo. Unfortunately, not before you had read it. :)
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